If voltage remains constant and resistance doubles, what happens to current according to Ohm's Law?

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Multiple Choice

If voltage remains constant and resistance doubles, what happens to current according to Ohm's Law?

Explanation:
With a fixed voltage, current is determined by I = V/R, so it varies inversely with resistance. If you double the resistance, the current must drop by the same factor. For example, using a constant 12 V source: at 6 Ω, current is 12/6 = 2 A. If the resistance increases to 12 Ω, current becomes 12/12 = 1 A. So the current is halved. This is why the correct result is that current halves. The other options would require the current to increase or stay the same, which contradicts the inverse relationship between current and resistance when voltage is constant.

With a fixed voltage, current is determined by I = V/R, so it varies inversely with resistance. If you double the resistance, the current must drop by the same factor.

For example, using a constant 12 V source: at 6 Ω, current is 12/6 = 2 A. If the resistance increases to 12 Ω, current becomes 12/12 = 1 A. So the current is halved.

This is why the correct result is that current halves. The other options would require the current to increase or stay the same, which contradicts the inverse relationship between current and resistance when voltage is constant.

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